Pembahasan Soal Vektor
U = 3 I – 3 I
V = 2 I – 4 j – 2 k
W = I + j + 2 k
U = (√32
–
32)2 = 18
V = (√22
+(- 42) +(- 22))2 = 24
W = (√ 12 + 12 + 22)2
= 6
Cos x = 6 +
24 – 18/2 √6 √24
Cos x =
12/24
Cos x = ½
X = 600
U = 3 I – 3 I
V = 2 I – 4 j – 2 k
W = I + j + 2 k
U = (√32
–
32)2 = 18
V = (√22
+(- 42) +(- 22))2 = 24
W = (√ 12 + 12 + 22)2
= 6
Cos x = 6 +
24 – 18/2 √6 √24
Cos x =
12/24
Cos x = ½
X = 600
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